<PRE><B>Question 709500</B>
You are saying this:
f(x)= 1 devided by      
        (3x+1)^5


If you try to solve for x when f(x)=1, then you will have your answer.  
f(x)=(3x+1)^5=1
What kind of number raised to any nonzero, non-one power give 1 as a result?


b^5=1, what must be b?
1^5=1, 1^-5=1, 1^30=1.....


If (3x+1)^5=1, then 3x+1=1.  {{{highlight(x=0)}}}


ANOTHER ATTEMPT TO EXPLAIN:
The question seems to be, for f(x)=(3x+1)^5, what is x if {{{(3x+1)^5=1}}}.  Solve for x.
Take the root 5 of both sides,
{{{3x+1=root(5,1)}}}
{{{3x+1=1}}}
Now subtract 1 from both sides,
{{{3x=0}}}
So what is x?  </PRE>