Question 709118
If you posted the actual question you have then it is a bad question for several reasons:<ul><li>What is "root"? Square root? cube root? 4th root? etc.</li><li>What is inside the radical (or whatever kind of root it is)? Just the 2? or 2/3?</li><li>The inverse functions take a ratio as input and provide an angle as output. Depending on what "root 2 over 3" means, it may be a valid ratio to be input to the inverse sin. But inverse sin will output an angle which is not valid input to inverse cos.</li></ul>If what you posted is not literally the problem given to you (which is waht I suspect), then please:<ul><li>Be more careful in posting. There is virtually no chance an inverse sin is input to an inverse cos.</li><li>Don't just say "root". Tell us what kind of root.</li><li>Use parentheses to tell us what is inside the radical of the root. Use
square root(2)/3 (or just sqrt(2)/3) for {{{sqrt(2)/3}}}
and use
square root(2/3) (or just sqrt(2/3)) for {{{sqrt(2/3)}}}</li></ul>