Question 62819
please solve
18y^4-42y^3
= 6y^3(3y-7)
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4y^2+25y+25 
=4y^2+20y+5y+25
=4y(y+5)+5(y+5)
=(y+5)(4y+5)
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54t3+16v3 
2(27t^3+8v^3)
=2(3t+2v)((3t)^2-(3t)(2v)+(2v^2))
=2(3t+2v)(9t^2-6tv+4v^2)
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y^2-3y-10=0
(y-5)(y+2)=0
y=5 or y=-2
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Cheers,
Stan H.