Question 709128
Using just #3 as an example:


You want the function which is the ratio of f to g, and then evaluate at x=2.

{{{f(x)/g(x)=(2x+3)/(x^2-x)}}}
and for x=2, evaluate this:
{{{(f/g)(2)=(2*2+3)/(2^2-2)}}}
and you can finish that.



Problem #4 is composition of functions.  g(x) is used as input to f(x), and the result is to be evaluated at x=5.


f(g(x))=2()+3,.... not finished.  We want to put g(x) into the missing parentheses position...
{{{f(g(x))=2(x^2-x)+3}}}
={{{2x^2-2x+3}}} --------we could use either form of the function.
NOW use x=5 and evaluate f(g(5)).