<PRE><B>Question 709063</B>
If the diagonal of a rectangle has length 14 feet, and the area of the rectangle is 64 square feet, find the number of feet in the perimeter of the rectangle.
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Draw a rectangle with one diagonal.
Let the sides be L and W
Then diagonal = sqrt[L^2+W^2]
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Equations:
sqrt(L^2+W^2) = 14 ft.
L^2 + W^2 = 196
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LW = 64 sq. ft
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L = 64/W
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Substitute for &quot;L&quot; and solve for &quot;W&quot;:
(64/W)^2 + W^2 = 196
64 + W^4 = 196W^2
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W^4 - 196W^2 + 64 = 0
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W^2 = 195.67
W = 13.99 ft
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Solve for L:
L = 64/W
L = 64/13.99
L = 4.57 ft
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Cheers,
Stan H.
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