Question 708134
{{{(2x-1)^2-x(10x+1) = x(1-x)(1+x)-(2-x)^3}}}
Alot of FOILing around here
{{{4x^2-4x + 1 - 10x^2 - x = x(1-x^2)-(4-4x+x^2)(2-x)}}}
Distribute; get rid of the brackets, change the signs where necessary
{{{4x^2 - 10x^2 - 4x - x + 1 = (x - x^3)-(8-12x+6x^2-x^3)}}}
{{{-6x^2-5x + 1 = x - x^3 - 8 + 12x - 6x^2 + x^3}}}
Combine like terms
{{{-6x^2-5x + 1 = -x^3 + x^3 - 6x^2 +  x + 12x - 8}}}
{{{-6x^2-5x + 1 = - 6x^2 + 13x - 8}}}
variables on the left, numbers on the right
{{{-6x^2 + 6x^2 - 5x - 13x = -8 - 1}}}
-18x = -9
x = -9/-18
x = +.5
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You should confirm this by replacing x with .5 in the original equation.
See that equality reigns supreme.