<PRE><B>Question 708813</B>
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Let *[tex \LARGE x] represent a postive multiple of 3.  Then *[tex \LARGE x\ +\ 3] is the next consecutive positive multiple of 3.  The sum of their squares is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ (x\ +\ 3)^2\ =\ 369]


Expand the squared binomial, collect like terms, put the quadratic into standard form, and solve.  Hint:  this quadratic is factorable.  Discard the negative root.  Verify that the positive root is, indeed, divisible by 3.  Then calculate *[tex \LARGE x\ +\ 3]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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