Question 708726
In any triangle, the angle opposite the shortest side is the smallest angle.
So angle C, opposite side AB is smaller than angle B, which measures {{{49^o}}}{{{B=49^o}}}.
{{{C<B}}} --> {{{C<=48^o}}}
{{{B+C<=49^o+48^o}}} --> {{{B+C<=97^o}}}
Since the measures of the angles of a triangle add up to {{{180^o}}},
{{{A+B+C=180^o}}} --> {{{A=180^o-(B+C)}}}
{{{B+C<=97^o}}} --> {{{180^o-(B+C)>=180^o-97^o}}} --> {{{180^o-(B+C)>=83^o}}} --> {{{A>=highlight(83^o)}}}