Question 708703
The probability of an event NOT happening is 1 - the probability of the event happening.
Eg. If there is a 25% chance of rain then the chance of NO rain is 1 - 25% (100% - 25%) = 75%
So in this problem
P{NOT ace OR heart}=1-P{ace OR heart}
the chance of getting an ace is 4 out of 52 ({{{4/52}}}) (This includes the ace of hearts)
the chance of getting a heart is 12 out of 52 ({{{12/52}}}) (can't include the ace in this as we've already counted it with the aces!)
Adding these fractions together
{{{4/52+12/52=16/52}}}
which simplifies to {{{4/13}}}
so now we have
{{{P(NOT_ace_OR_heart)=1-4/13}}}
giving
{{{P(NOT_ace_OR_heart)=9/13}}}