<PRE><B>Question 708486</B>
How do I solve for the sides of a rectangle when given only the perimeter (40 feet) and the square feet (90 sq. ft)? 
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P = 2(L+W)
40 = 2(L+W)
L + W = 20
L = (20-W)
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A = LW
90 = (20-W)W
-W^2 +20W = 90
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W^2 -20W + 90 = 0
W = 13.16
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L = 20-W = 6.84
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Cheers,
Stan H.
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