<PRE><B>Question 708476</B>
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You wrote:

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Speeding car 80 x+10 80(x+10)
Police Car 100 x 100x 
80(x+10)=100x
80x+800=100x
800=20x
40=x Incorrect to the book answer 
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Which is NOT incorrect to the book answer.  Since you wrote *[tex \LARGE 80(x + 10)], and the time differential was given as 10 seconds, your unit of measure for *[tex \LARGE x] has to be seconds as well.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{40s}{60s/m}\ =\ \frac{2}{3}] minute.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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