Question 62775
{{{ x^3+2x^2+3x=0 }}}
factor out an x
{{{ x(x^2+2x+3)=0 }}}
the Trinomial will not factor, so use the Quadratic equation
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
a=1
b=2
c=3
{{{x = (-2 +- sqrt( 2^2-4*1*3 ))/(2*1) }}}
work what is under the root first
{{{x = (-2 +- sqrt( 4-4*1*3 ))/(2*1) }}}
{{{x = (-2 +- sqrt( 4-12 ))/(2*1) }}}
{{{x = (-2 +- sqrt( -8 ))/(2*1) }}}
Work the denominator
{{{x = (-2 +- sqrt( -8 ))/2 }}}
work the negative root
{{{x = (-2 +- 2i (sqrt( 2 )))/2 }}}
reduce the fraction
{{{x = (-1 +- 1i (sqrt( 2 )))/1 }}}
{{{x = -1 +- 1i (sqrt( 2 )) }}}
This is 2 of your answers, the other is x=0 .... the one we factored out at the beginning.