Question 708299
Please help me solve this problem: log1/3(x^2+x)-log1/3(x^2-x)=-1. Do you have to divide the two logs because there is subtraction, or is there another way? yes, that's the correct approach.
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I'm going to assume you meant log base (1/3):
{{{log(1/3,x^2+x)-log(1/3,x^2-x)=-1}}}
{{{log(1/3,(x^2+x)/(x^2-x))=-1}}}
{{{log(1/3,x(x+1)/x(x-1))=-1}}}
{{{log(1/3,(x+1)/(x-1))=-1}}}
{{{(x+1)/(x-1)=(1/3)^(-1)}}}
{{{(x+1)/(x-1)=1/(1/3)^1}}}
{{{(x+1)/(x-1)=1/(1/3)}}}
{{{(x+1)/(x-1)=3}}}
{{{(x+1)=3(x-1)}}}
{{{x+1=3x-3}}}
{{{1=2x-3}}}
{{{4=2x}}}
{{{2=x}}}