Question 62769
The given equation is y = x^2 + x - 6

This is of the form ax^2 + bx + c = y

The x co-ordinate of the vertex = -b/2a

                                = -1/2*1

                                = -1/2


Replacing x by -1/2 in the given equation,

y = (-1/2)^2 + (-1/2) - 6

  = 1/4  - 1/2  - 6

  = -1/4  - 6

  = - 6 1/4

The vertex = (-1/2, - 25/4)

To find the y intercept we replace x by 0.

==> y = 0 + 0 -6

==> y = - 6

To find the x intercept we set y = 0

==> x^2 + x - 6 = 0

==> x^2 + 3x - 2x - 6 = 0

==> x(x+3) - 2(x+3) = 0

==> (x+3)(x-2)= 0

==> x+ 3 = 0  or  x - 2 = 0

==> x = - 3  or x = 2

Thus the x intercepts are -3 and 2 while the y intercept is -6


Good Luck!!!