Question 708139
I'll show most of the way through a solution but not the whole finished solution.


From this given, {{{2*log(9,(3x-1))=log(9,(6x+1))}}}, you can form
{{{log(9,(3x-1)^2)=log(9,(6x+1))}}}
and since this shows taking logarithms on each side, we can equate the expressions  of which those logarithms are being taken:


{{{(3x-1)^2=(6x+1)}}}
.
{{{9x^2-12x=0}}}.  Divide L & R by 3:
{{{3x^2-4x=0}}}.
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