Question 62754
Given an equation y = -x^2 + 6x

Where a = -1, b = 6

Since the a < 0, we have a maximum value.

x = (-b /2a) = -6 /2 * -1 = 6 /2 = 3

x = 3

Put x =3 in equation(1), we get

y = -(3)^2 + 6 * 3 = -9 + 18 = 9

Therefore the maximum value is given by 9.