Question 707803
Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(4)+-sqrt((4)^2-4(1)(-10)))/(2(1))}}} Plug in {{{a = 1}}}, {{{b = 4}}}, {{{c = -10}}}


{{{x = (-4+-sqrt(16-(-40)))/(2)}}}


{{{x = (-4+-sqrt(16+40))/(2)}}}


{{{x = (-4+-sqrt(56))/2}}}


{{{x = (-4+sqrt(56))/2}}} or {{{x = (-4-sqrt(56))/2}}}


{{{x = (-4+2*sqrt(14))/2}}} or {{{x = (-4-2*sqrt(14))/2}}}


{{{x = -2+sqrt(14)}}} or {{{x = -2-sqrt(14)}}}