<PRE><B>Question 707798</B>
3a-4 the larger number.
3a-6 the smaller number.
Multiply thes e2 numbers.
3a-4
3a-6
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9a^2-12a-18a+24
9a^2-30a+24
3(3a^2-10a+8)
3(3a-4)(a-2) ans.</PRE>