<PRE><B>Question 62755</B>
y = x^2 - 8x + 22 


This represents a parabola of the standard form y = ax^2 + bx + c

The x co-ordinate of the vertex is given by -b/2a

Thus the x co-ordinate = -(-8)/2*1

                     = 8/2
                    = 4

Substituting x = 4 in the given equation,

y = 4^2 - 8*4 + 22

  = 16 - 32 + 22

  = 6

So the vertex of the given parabola is (4,6)

Good Luck!!!</PRE>