Question 62745
<b>logx(9)=-1/3</b>

If logx(9)=-1/3 then {{{x^(-1/3)=9}}}.
Cube both sides. Then, {{{(x^(-1/3))^3=9^3}}}.
Or, {{{x^-1 = 9^3}}}.
Now, raise both sides to the -1 power.
Then, {{{(x^-1)^-1 = (9^3)^-1}}}.
Or, {{{x=9^-3}}} or {{{x=1/9^3=1/279}}}.

To verify the answer plug {{{x=9^-3}}} into {{{x^(-1/3)=9}}}
and you get {{{(9^-3)^(-1/3) = 9^(3*1/3) = 9^1 = 9}}}.