Question 706845
{{{18a^2b^3c-45ab^6c}}} has just two terms: {{{18a^2b^3c}}} and {{{45ab^6c}}}
The numeric coefficients have {{{9}}} as a common factor:
{{{18=9*2}}} and {{{45=9*5}}}
The variable {{{a}}} appears as {{{a}}} in one term and as {{{a^2=a*a}}} in the other,
so {{{a}}} is a factor common to both terms.
The variable {{{b}}} appears as {{{b^3}}} in one term and as {{{b^6=b^3*b^3}}} in the other,
so {{{b^3}}} is a factor common to both terms.
The variable {{{c}}} appears as {{{c}}} in both terms,
so {{{c}}} is a factor common to both terms.
Taking out common factors,
{{{18a^2b^3c=9ab^3c(2a))}}} and
{{{-45ab^6c=9ab^3c(-5b^3)}}}, so
{{{18a^2b^3c-45ab^6c=9ab^3c(2a-5b^3)}}}