Question 707295
a) {{{ y= x^4 + 2 }}}
Differentiating wrt x:
{{{ dy/dx=4x^3 }}}
At a Turning Point {{{ dy/dx=0 }}} so
{{{ 4x^3 = 0 }}} giving {{{ x =0 }}}
When {{{ x =0 }}}, {{{ y=0+2=2 }}}

So TP has coordinates (0,2)


b) {{{ y= 7 - 2x^4 }}}
Differentiating wrt x:
{{{ dy/dx=-8x^3 }}}
At a Turning Point {{{ dy/dx=0 }}} so
{{{ -8x^3 = 0 }}} giving {{{ x =0 }}}
When {{{ x =0 }}}, {{{ y=7-0=7 }}}

So TP has coordinates (0,7)