Question 707057
The description literally gives this, and expecting implied past and future ages:

Now: {{{a=h/2}}}
Seven years in future: {{{a+7=(3/5)(h+7)}}}
Seven years in the past: {{{a-7=(1/3)(h-7)}}}


Three equations and two unknown variables.  Chance for conflict.?


The futures question gives us {{{5a-3h=-14}}},[multiplied members by 5 first].
The past question gives us {{{3a-h=14}}}, [multiplied members by 3 first].
Multiply this "past" equation by -3 and add to the future equation, giving
4a=56
{{{a=14}}}.  So Ann is 14 now.  


Without looking too deeply more, Henry would be twice that now, being 28.