Question 62730
3x – 4y < 12 
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Solve for y as follows:
3x-12<4y
y>(3/4)x-3
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Now, graph the EQUALITY y=(3/4)x-3 as a dashed line
If x=0, y=-3 ; If x=4, y=0
Plot the two points (0,-3) and (4,0)
Draw a dashed line thru those points.
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Since you want to graph y GREATER THAN (3/4)x-3
you should shade the half-plane ABOVE the dashed line.
That is the graph of the INEQUALITY.
Note: The dashed line is not part of the graph; it 
indicates the boundary line of the graph.
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I'll graph the line below so you see what it looks like:
{{{graph(300,200,-10,10,-10,10,(3/4)x-3)}}}
Cheers,
Stan H.