Question 706998
The information from the description is this:
p=2000
r=unknown
a=3000
n=12  (because the year is cut into 12 equal parts, meaning "monthly")
t=10


Keep all as symbols, solve for r, AND THEN substitute the values.
As I OMIT most of the symbolic steps, the equation you will have is
{{{log(10,(1+r/n))=(log(10,a)-log(10,p))/(nt)}}}
(start by taking logarithm of both sides...).
... I am here referring to log base TEN (but you could choose whatever base you like).


Do not be hung-up with the (1+r/n) number.  It just represents the monthly interest rate.  Just solve for (1+r/n), and when you have this value, you can then proceed to find r, the yearly rate, because you already know n.