<PRE><B>Question 706989</B>
graph the relation 3y= 9x^2-6x+12
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Simplify:
y = 3x^2 - 2x +4
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Vertex occurs where x = -b/2a = 2/(6) = 1/3
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f(1/3) = 3(1/9) - (2/3) + 12/3 = 11/3
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Plot the vertex at (1/3 , 11,3)
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y-intercept = f(0) = 4
Plot (0,4)
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Sketch a parabola thru those points opening upward.

{{{graph(400,400,-10,10,-10,10,3x^2-2x+4)}}}
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Cheers,
Stan H.
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