Question 706945

let number be {{{x}}}

{{{4}}} times the {{{sum }}}of a number {{{x}}} plus {{{3}}}: {{{4(x+3)}}}


is {{{equal}}} to 

{{{14}}} times the {{{difference}}} of the number {{{x}}} and {{{2}}}:{{{14(x-2)}}}

so, we have

{{{4(x+3)=14(x-2)}}}......now solve for {{{x}}}

{{{4x+12=14x-28}}}

{{{28+12=14x-4x}}}

{{{40=10x}}}

{{{40/10=x}}}

{{{4=x}}}