Question 706825
The area will be the area of the rectangular part, plus the area of the semicircular part.
 
For the second part:
If the radius is {{{2}}}ft, the diameter, which is also the width of the rectangle, is
{{{2*2ft=4}}}ft.
That would be the base of the downwind.
and if the height of the rectangular part is twice the base, then that height is
{{{2*4}}}feet={{{8}}}feet.
Then the area of the rectangular part is {{{(4ft)(8ft)=32ft^2}}}
The area of half of a circle with radius {{{2ft}}} is
{{{(1/2)pi*2^2ft^2=(1/2)4pi}}}{{{ft^2=2pi}}}{{{ft^2}}}
The total area is
{{{32ft^2+2pi}}}{{{ft^2=highlight((32+2pi))}}}{{{ft^2}}}= approximately{{{(32+6.28)ft^2=highlight(38.28)ft^2}}} .
 
For the first part, a rectangle 3 feet by 6 feet would have an area of 72 square feet, and a semicircle with a 6 feet diameter (3 feet radius) would have an area of
{{{(1/2)pi*3^2ft^2=(9/2)pi}}}{{{ft^2}}}=approximately {{{14.14ft^2}}},
for a total area of approximately {{{86.14ft^2}}}.
That is what you found, aside from the rounding difference.
(I used a more accurate version of {{{pi}}}, but I would get 86.13 too, If I used 3.14 por {{{pi}}}).