Question 706856
Two friends and I have posted this problem: It isn't registering on their emails. ???? I got one response saying problem was impossible. Its a text book problem. All of us are stumped, please help asap, due monday.
A norman window. Rectangle portions height is twice the base. Base equals 6 feet. It has a semicircular top. What is the area of window? I got 86.13.
Now, if that same window's semicircular top has a radius of 2 feet, and we want the area of the rectangular part of window to have same area as the semicircular top, what would the dimensions of the rectangular part of window be?
:
It is impossible. and contradictory, the base of the window is the width of the window. The width is also equal the diameter of the half circle on the top which is given as a radius of 2 ft, therefore the width is the diameter which is 4ft (draw this out and it will be apparent)
The first paragraph gives the base a 6ft, they are talking about two different windows.

If we ignore the 1st paragraph and just solve: 
"The window's semicircular top has a radius of 2 feet, and we want the area of the rectangular part of window to have same area as the semicircular top, what would the dimensions of the rectangular part of window be?
:
Find the area of the semicircular top
A = {{{1/2}}}*{{{pi*r^2}}}
A = {{{1/2}}}*{{{pi*2^2}}}
A = 6.283 sq/ft
:
They want the area of the rectangular portion = 6.283 sq/ft also
:
The area of the rectangle:
 H * W = 6.283
We know the width is 4 ft
H * 4 = 6.283
H = 6.283/4
h = 1.57 ft is the height of the window
:
the dimensions of the rectangular portion, 1.57 by 4 ft