Question 706712
<pre>
4a² + 12a + 9 - 16b²

Group the first three terms:

(4a² + 12a + 9) - 16b²

Factor the part in parentheses:

(2a+3)(2a+3) - 16b²

(2a+3)² - (4b)²

That's the difference of squares:

[(2a+3) - 4b][(2a+3) + 4b]

(2a + 3 - 4b)(2a + 3 + 4b)

Edwin</pre>