Question 62712
{{{M^8N^6/M^4N^2}}}
This could be expanded out as
{{{(M*M*M*M*M*M*M*M*N*N*N*N*N*N)/(M*M*M*M*N*N)}}} You could then cancel out matching M's or N's on the top and bottom to get
{{{M*M*M*M*N*N*N*N)}}}
Which would be the same as
{{{M^4N^4}}}
I would assume however that you are expected to use the Index Division Law
{{{M^a/M^b=M^(a-b)}}} to sove it directly.
{{{M^8N^6/M^4N^2=M^(8-4)N^(6-4)=M^4N^4}}}