Question 706295
 i am trying to figure out the lengths of the sides of a triangle i have the height
and the angle but nothing else. 
overall height is 4 feet
angles are 60 deg.
60 deg.
60 deg.
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Sketch an equilateral triangle with each side = 2s.
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Draw an altitutde from one of the sides to the opposite vertex.
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That altitude is a perpendicular bisector of the base.
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Each piece of that base is "s".
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Now use Pythagoras to solve for "2s".
base = s
altitude = 4
hypotenuse = side of the triangle = 2s
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(2s)^2 = s^2 + 4^2
4s^2 = s^2 + 16
3s^2 = 16
s^2 = 16/3
s = 4sqrt(3)/3
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side = 2s = (8/3)sqrt(3)
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Cheers,
Stan H.
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