Question 705842
Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(-5)+-sqrt((-5)^2-4(-2)(27)))/(2(-2))}}} Plug in {{{a = -2}}}, {{{b = -5}}}, {{{c = 27}}}


{{{x = (5+-sqrt(25-(-216)))/(-4)}}}


{{{x = (5+-sqrt(25+216))/(-4)}}}


{{{x = (5+-sqrt(241))/(-4)}}}


{{{x = (5+sqrt(241))/(-4)}}} or {{{x = (5-sqrt(241))/(-4)}}}


{{{x = (-5-sqrt(241))/(4)}}} or {{{x = (-5+sqrt(241))/(4)}}}


{{{x = (-5+sqrt(241))/(4)}}} or {{{x = (-5-sqrt(241))/(4)}}}


Solutions: {{{x = (-5+sqrt(241))/(4)}}} or {{{x = (-5-sqrt(241))/(4)}}}


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Jim


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