Question 705740
Finding the real solutions to the equation:

Please help me solve this: 5x^2/3-24x^1/3-5=0
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Sub u for x^(1/3)
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5u^2 - 24u - 5 = 0
(5u + 1)*(u - 5) = 0
u = 5
x^(1/3) = 5
x = 125
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u = -1/5
x = -1/125