Question 705674
given cos theta = 2/3 and sin theta > 0 find:
all angles in quadrant I where cos and sin>0
let O=opposite side
let A=adjacent side
let H=hypotenuse
given cos theta=2/3=A/H
A=2, H=3
O=√(3^2-2^2)=√(9-4)=√5
sin theta =O/H=√5/3
tan theta =O/A=√5/2
cot theta =2/√5
sec theta =3/2
csc theta = 3/√5