Question 705651
Positive powers of ten move the decimal point to the right.
i.e.{{{3.12X(10)^3}}}=3120, the point has moved 3 places right.
Negative powers of 10 move the decimal point to the left.
i.e.{{{2.5X(10)^-2}}}=0.025, point has moved 2 places left
So in your problem
{{{5.4X(10)^-4}}}=0.00054 and {{{6X(10)^-7}}}=0.0000006