Question 705638
{{{- log x - 4log y + 5log(x +1)}}} (this and following steps showing up wrong)
= {{{-1(log(x)+log(y))+5log(x+1)}}}
= {{{-1(log(xy))+5log(x+1)}}}
= {{{5*log(x+1)-log(xy)}}}
= {{{log(x+1)^5-log(xy)}}}
= {{{log((x+1)^5/(xy))}}}, the answer. Yes, correct.

(again, still learning some of the typesetting.  Some of the steps are not showing up correctly.)


In plain text, the steps are
-1(log(x)+log(y))+5log(x+1)
= -1(log(xy))+5log(x+1)
= 5*log(x+1)-log(xy)
= log(x+1)^5-log(xy)