Question 62562
{{{y = 4x^2 + 16x + 23}}}
Use quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-16 +- sqrt( 16^2-4*4*23 ))/(2*4) }}}
{{{x = (-16 +- sqrt( 256 - 368 ))/8 }}}
{{{x = (-16 +- sqrt( -112 ))/8 }}}
{{{x = -2 + 10.583*i / 8 }}} and
{{{x = -2 - 10.583*i / 8 }}}
------------------------
simplified
{{{x = -2 + 1.323*i}}}
{{{x = -2 - 1.323*i}}}