Question 705614
6/y+2+1/y-2=1
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6/(y+2) + 1/(y-2) = 1
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Multiply thru by (y+2)(y-2) to get:
6(y-2) + 1(y+2) = (y+2)(y-2)
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6y-12 + y+2 = y^2-4
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y^2 -7y +6 = 0
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Factor:
(y-6)(y-1) = 0
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y = 1 is an extraneous solution:
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y = 6 is a valid solution.
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Cheers,
Stan H.
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