Question 705493
(-4,1) and has the same slope as the line whose equation is 4x-3y=5

4x-3y=5

3y=4x-5

/3
y=(4/3)x-(5/3)

compare with equation 
y=mx+b

m=4/3

equation of line passing through (-4,1)(x1,y1) and slope (4/3)

y-y1= m(x-x1)

y-1=(4/3)(x-(-4))

y-1= (4/3) (x+4)

multiply equation by 3
3(y-1) = 4(x+4)

3y-3=4x+16
4x-3y= -19