Question 62663
<b>Please help me solve this question. What is the average of 3^22, 3^23 and 3^24</b>

Let the three numbers to average be a, b, and c.

So, {{{a=3^22}}}.
Then {{{a*3=3^(22+1)=3^23=b}}}.
Also, {{{a*3*3=3^(22+2)=3^24=c}}}.

So, {{{b=3*a}}} and {{{c=9*a}}}.
So, the three numbers to average, in terms of a, are a, 3*a, and 9*a.

You get the average of three numbers by adding them up and dividing by 3.
So, the average is: {{{(a+3a+9a)/3 = 13a/3}}}.
Put {{{a=3^22}}} back into the equation and the average is: {{{13(3^22)/3}}}.
But, {{{3^22/3 = 3^21}}} so the average is {{{13(3^21)}}}.