Question 705310
Find all real zeros of the function g(x)=x^3+4x^2-x-4
.
Possible zeros:
4/1 = +-[1,2,4]
.
Using synthetic division try 1:
1 | 1  4  -1  -4
       1   5   4
   --------------- 
    1  5   4   0
since we have a zero remainder, we know 1 is a root.
So, it factors to:
(x-1)(x^2+5x+4)
Now, we can factor (using normal methods):
(x-1)(x+4)(x+1)
Real zeros are at 
x={1, -4, -1}