<PRE><B>Question 705333</B>
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Use the two-point form of an equation of a line to derive the volume as a function of depth equation.  The two points being (66,4) and (33,6).


Then use the two-point form again to derive the volume as a function of pressure equation with the points (3,4) and (2,6).


&lt;b&gt;Two Point Form&lt;/b&gt;


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


Once you have done the arithmetic to simplify your equations, a graph and a table is trivial.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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