Question 705256
Let the fraction be x/y.

So, (x-1)/y = 1/2  multiply each term by 2y
2(x-1)=y or 2x-2=y and 2x-y=2----eq1
x/(y+7)=1/3 multiply each term by 3(y+7)
3x=(y+7)or 3x-y=7----eq2

Subtract eq1 from eq2 and we get:
x=5------------numerator
Substitute x=5 into eq1:
2*5-y=2
10-y=2
-y=-8
y=8 ----denominator
CK
(5-1)/8=4/8=1/2  ---ok
5/(8+7)=5/15=1/3---ok

Hope this helps---ptaylor