Question 705256
If fraction is {{{ x/y }}}


if 1 is subtracted from the numerator of a fraction, the value of a resulting fraction is 1/2.  
{{{ (x-1)/y = 1/2 }}}
{{{ 2(x-1) = y }}}
{{{ 2x-2 = y }}}
{{{ 2x-y = 2 }}}



However, if 7 is added to the denominator of the original fraction, the value of the resulting fraction is 1/3.  Find the original fraction
{{{ x/(y+7) = 1/3 }}}
{{{ 3x = y+7 }}}
{{{ 3x-y = 7 }}}



*[invoke solving_linear_system_by_substitution 2, -1, 2, 3, -1, 7]