Question 705115
1a)


x < 0, so x is negative


y > 0, so y is positive


This means y^2 is positive and so is y^2 divided by y


Multiply this positive number (y^2 divided by y) with a negative number (x) to get


xy^2 over y


and this result will be negative since negative times positive = negative.


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1b)


x^2 is always positive regardless if x is positive or negative


1 - x^2 is positive only if x^2 < 1 or if  -1 < x < 1


1 - y is positive only if y < 1


Since x < 0, we know for a fact that 1 - x^2 is negative (see the rule above)


Because y > 0, we know that 1-y is negative (again, look at the rule)


So 1-x^2 is negative when x < 0 and 1-y is negative when y > 0


Therefore 1-x^2 divided by 1-y  is positive  (negative/negative = positive)