Question 705005
y=x^2+7x


-12=a^2+7a


0=a^2+7a+12


a^2+7a+12 = 0


(a+4)(a+3) = 0


a+4=0 or a+3=0


a=-4 or a=-3


Answer: a=-4 or a=-3


Therefore, the points on y=x^2+7x are (-4, -12) and (-3, -12)