<PRE><B>Question 704977</B>
Steps:
log(2x+1)-log(x-2)=1 
log((2x+1)/(x-2))=1  [property of logarithms]


You need to know which base to continue.  Is the base 10, or 2, or e?  If base is 10, then  (2x+1)/(x-2)=10, 
2x+1=10x-20,
1=8x-20
-19=8x,
x=-19/8

Is base 2?
(2x+1)=2(x-2)
2x+1=2x-4
False

Is the base e?</PRE>