Question 704977
what is the answer for 
log(2x+1) = 1 + log (x-2)
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log(2x+1) - log(x-2) = 1
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log[(2x+1)/(x-2)] = 1
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(2x+1)/(x-2) = 10^1
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Cross-multiply
2x+1 = 10(x-2)
2x + 1 = 10x -20
8x = 21
x = 21/8
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Cheers,
Stan H.
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