Question 704904
MARY=Y
FATHER=4Y
MOTHER=4Y-7
Y+4Y+4Y-7=101
9Y=101+7
9Y=108
Y=108/9
Y=12 AGE OF THE DAUGHTER.
4*12=48 AGE OF THE FATHER.
48-7=41 AGE OF THE MOTHER.
PROOF:
12+48+41=101
101=101